A 95 kg football player runs straight up the field at 7.2 m/s. He is tackled by

Question

A 95 kg football player runs straight up the field at 7.2 m/s. He is tackled by a 119 kg player running across the field at an angle of 35° to the horizontal at 5.8 m/s. In what direction (in degrees) and at what velocity will they move together immediately after impact? (The direction should be measured relative to the direction straight up the field: For instance, if both players kept moving straight up the field, we would say that the direction was 0 degrees; if they moved directly across the field, we would call that direction 90 degrees.)

Explanation / Answer

m1u1 + m2u2 = (m1+m2)V

95*7.2 j - 119*(5.8cos(35)i + 5.8sin(35)j ) = (95+119)v

95*7.2 j - 119*(5.8*0.81 i + 5.8*0.57 j= (95+119)v

-559.062 i + 644.6 j = 214v

v = -2.61i + 3.01j ( combined velocity of both )

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