A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally

Question

A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 51.0 m/s and returns the shot with the ball traveling horizontally at 38.0 m/s in the opposite direction. (Take the direction of the ball's final velocity (toward the net) to be the +x-direction.)

(a) What is the impulse delivered to the ball by the racket?

(b) What work does the racket do on the ball? (Indicate the direction with the sign of your answer.)
___________________J

Explanation / Answer

initial momentum=-0.06*51(since it is in-ve x direction)=- 3.06Ns

final momentum=0.06*38=2.28Ns

impulse=change in momentum=2.28-(-3.06)=5.34Ns

direction is in +ve X direction

Work done by racket=change in K.E of the ball = 1/2*0.06(382-512)

=-2557.68J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.