A block m_1 rests on a frictionless surface. A second block m_2 sits on top of t

Question

A block m_1 rests on a frictionless surface. A second block m_2 sits on top of the first block. Here m_1 = m_2 = m. A horizontal force F is applied to the bottom block to pull it to the right as shown below. Assume that the blocks move together across the surface (block m_2 does not slide off of block m_1). What is the magnitude of the acceleration of the blocks? (Use the following as necessary: m, g, and F.) What are the magnitude and direction of the static friction force acting on m_1 due to m_2? (Use the following as necessary: m, g, and F.) What are the magnitude and direction of the static friction force acting on m_2 due to m_1? (Use the following as necessary: m, g, and F.)

Explanation / Answer

a) a = F/(m1+m2)

b) f = m2*a

direction : -x

c) f = m2*a

direction : +x

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