A) Using the value of 1 BTU per pound water per degree Fahrenheit, use the corre
ID: 1357127 • Letter: A
Question
A) Using the value of 1 BTU per pound water per degree Fahrenheit, use the correct unit conversions to convert this to 4.186 Joules per gram water per kelvin b) Using an R value of 1 square foot hour Fahrenheit per BTU, show the correct unit conversions to get the conversion factor to square meter Kelvin per watt A) Using the value of 1 BTU per pound water per degree Fahrenheit, use the correct unit conversions to convert this to 4.186 Joules per gram water per kelvin b) Using an R value of 1 square foot hour Fahrenheit per BTU, show the correct unit conversions to get the conversion factor to square meter Kelvin per watt A) Using the value of 1 BTU per pound water per degree Fahrenheit, use the correct unit conversions to convert this to 4.186 Joules per gram water per kelvin b) Using an R value of 1 square foot hour Fahrenheit per BTU, show the correct unit conversions to get the conversion factor to square meter Kelvin per wattExplanation / Answer
(A)
The conversion rates are as follows.
1 BTU = 1055.06 Joules
1 Pound = 453.592 grams
1 Fahrenheit = 255.928 Kelvin
1 BTU / (1 pound * 1 Fahrenheit) = 1055.06 Joules / (453.592 grams * 255.928 Kelvin)
1 BTU = 9.0885 * 10-3 Joule / gm-kelvin
(B)
Given R = 1 square foot hour Fahrenheit per BTU
Conversion rates are as follows.
1 foot = 0.3048 meters
1 hour = 60 * 60 = 3600 seconds
1 Fahrenheit = 255.928 Kelvin
1 BTU = 9.0885 * 10-3 Joule / gm-kelvin [From Part A]
Now, R = 1 foot2 * hour * Fahrenheit / BTU
=> R = 1 * (0.3048)2 metre2 * 3600 seconds * 255.928 Kelvin / (9.0885 * 10-3 Joule / gm-kelvin)
=> R = 9.418 * 106 metre2 * seconds * Kelvin * gm * kelvin / Joule
=> R = 9.418 * 106 metre2 * Kelvin * gm * kelvin / (Joule / seconds)
we know Joule / second = Watt
=> R = 9.418 * 106 (metre * Kelvin)2 * gm / Watt
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