A puck of mass m = 1.13 kg slides in a circle of radius r = 10.5 cm on a frictio

Question

A puck of mass m = 1.13 kg slides in a circle of radius r = 10.5 cm on a frictionless table while attached to a hanging cylinder of mass M = 2.04 kg by means of a cord that extends through a hole in the table (as shown in the figure). What is the required force of tension on M to keep it from falling? Submit Answer Tries 0/5 How do the tensions acting on M and m compare? Incorrect The tension on M is greater than the tension on m. Incorrect The tension on M is less than the tension on m. Correct: They are equal. You are correct. Your receipt no. is 156-1963 What is speed of the puck that keeps the cylinder at rest? Submit Answer Tries 0/5

Explanation / Answer

Required tension, T = M*g

= 2.04*9.8

= 20 N <<<<<<--------Answer

Let v is the required speed.

now Apply, T = m*a

T = m*v^2/r

==> v = sqrt(T*r/m)

= sqrt(20*0.105/1.13)

= 1.36 m/s <<<<<<--------Answer

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.