1. A spring with a spring constant k- 13.5 N/m has a 300 gm mass hanging off of
ID: 1355130 • Letter: 1
Question
1. A spring with a spring constant k- 13.5 N/m has a 300 gm mass hanging off of it. The mass is displaced 10 em below equilibrium, held at rest, and then released. What is the amplitude of the oscillation (easy), and the frequency of the oscillation (still pretty easy)? (a) (b) What is the total energy of the oscillator? Remember that if you use the elastic energy at the extremal position, you don't need to add in a kinetic term, since at the ends, KE-0 (c) What is the maximum velocity of the oscillator? Using the energy is the simplest way to get the answer.Explanation / Answer
1)
here , mass , m = 0.300 gm
k = 13.5 N/m
a) amplitude , A = 0.10 m
frequency = sqrt(k/m)/2pi
frequency = sqrt(13.5/0.3)/(2 * 3.141)
frequency = 1.07 Hz
the frequency is 1.07 Hz
b)
Total energy = 0.5 * k * x^2
Total energy = 0.5 * 13.5 * 0.1^2
Total energy = 0.0675 J
c)
for the maximum velocity
0.5 * 0.3 * v^2 = 0.0675
v = 0.67 m/s
the mmaximum velocity is 0.67 m/s
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.