While remodeling your garage, you need to temporarily splice, end to end, an 80

Question

While remodeling your garage, you need to temporarily splice, end to end, an 80 m long copper wire that is 1.11 mm in diameter with a 49 m long aluminum wire that has the same diameter. The maximum current in the wires is 2.00 A.

9. -/10 points Tipler6 25·P.044 While remodeling your garage, you need to temporarily splice, end to end, an 80 m long copper wire that is 1.11 mm in diameter with a 49 m long aluminum wire that has the same diameter. The maximum current in the wires is 2.00 A My Notes + (a) Find the potential drop across each wire of this system when the current is 1.83 A V (copper wire) V (aluminum wire) (b) Find the electric field in each wire when the current is 1.83 A. mV/m (copper wire) mV/m (aluminum wire) eBook

Explanation / Answer

for copper wire

copper: L = 80 m,

Diameter d = 1.19 mm

resisitivity = 1.72*10-8m,

resistance R = 4 rho L/( Pi d2)

aluminum: L' = 49 m,

d = 1.11 mm,

' = 2.75*10-8m,

resistance R' = Rho L/A = 4'L'/( pi d2)

I = 1.83 A

a) from ohms law V = iR

here for copper VCu = IR

V = 1.83 * 1.72 e -8 * 80/(3.14* 0.595 e -3 * 0.595 e -3)

V = 2.26 V

VAl = 1.83 * 2.75 e -8 * 49/(3.14* 0.595 e -3 * 0.595 e -3)

V = 2.21 Volts

part B

use E of Copper = VCu/L = 2.26/80 = 28.25 mV/m

EAl = VAl/L = 2.21/49 = 45.1 mV/m

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