E MasteringPhysics: Ch o7 HW (Part 1) Google Chrome session masteringphysics.com

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E MasteringPhysics: Ch o7 HW (Part 1) Google Chrome session masteringphysics.com 51476041 https:// www.citadel.edu/ro signed in as Isaac Lamberth I Help I Close A COLLEGE PHYS-203 fa2015 Ch 07 HW (Part 1) A Relation Between Momentum and Kinetic Energy Resources previous l 5 of 21 l next A Relation Between Momentum and Kinetic Energy Part A s answer all questions. A cardinal (Richmondena cardinalis) of mass 4.10x10-2 kg and a baseball of mass o.145 kg have the same kinetic energy. What is the ratio of the cardinals e typically answered within 2 magnitude pc of momentum to the magnitude pb of the baseball's momentum? questions per month er, faster answers Submit Hints My Answers Give Up Review Part Part B A man weighing 700 N and a woman weighing 400 N have the same momentum. What is the ratio of the man's kinetic energy Km to that of the woman Kw? Submit Hints My Answers Give Up Review Part Continue Provide Feedback RESOURCES TEXTBOOK LINKS COMPANY ABOUT CHEGG STUDENT SERVICES HE Search the web and Windows 12:23 PM 11/3/2015

Explanation / Answer

PART A

p refers to momentum

momentum = m v and KE = 1/2 m v^2

so we can write momentum as

KE = p^2/2m (p=mv; p^2 = m^2 v^2; p^2/2m = m^2 v^2/2m = m v^2/2 = KE)

so if the KE's are equal, the ration of p^2/2m are equal

so

pc^2/2 mc = pb^2/2 mb

(pc/pb) = Sqrt[mc/mb] = Sqrt[4.10x10^-2/0.145] = 0.53 ANSWER

PART B

mass of man = 700 / 10 = 70 kg
mass of woman = 400/10=40 kg

70 * v = 40 * v1

v / v1 = 40 / 70 =

ratio of KE

0.5 * 70 * v ^2 / 0.5 * 40 * v1 ^2

= 70 / 40 * ( 40/75 ) ^2

= 40 / 70

= 4 / 7

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