E C HW 2.9 Applied Optimi: K https://smccd.instructure.com/courses/14464/assignm

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E C HW 2.9 Applied Optimi: K https://smccd.instructure.com/courses/14464/assignments/163588 Luis Canjura Sorto Announcements Assignments Discussions Grades People Pages Files Syllabus Quizzes Modules Conferences Collaborations MH Campus MH Connect Google Drive Title IX Accessibility Total Points Possible: 20 Suppose a company's revenue function is given by R(g)300g2 and its cost function is given by C(g) 560+14q. where q is hundreds of units sold produced, while R(g) and C(g) are in total dollars of revenue and cost, respectively C Q 1 (0.8/1) Q2 (0.5/1) A) Find a simplified expression for the marginal profit function (Be sure to use the proper variable in your answer.) C Q4 (0.6/1) Q5 [11] C Q7 (0.7/1) B) How many items (in hundreds) need to be sold to maximize profits? (Round your answer to two decimal places.) hundred units must be sold. C Q 10 (0.6/1) Get help: Video Inbox Q12 [1/1] ? Q 13 (0/1) Points possible: 1 Unlimited attempts. Score on last attempt: (0, 0), Score in gradebook: (0, 0), Out of: (0.5, 0.5) Message instructor about this question Q 14 [1/1] Q 15 (0/ 1) Q 16 [1 / 1] Q 17 (0/1) ? Q 18 (0.41) Q 19 (0/ 1 ) Q 20 [111] Help Submit Grade: 13.6/20 Print Version Course Chat S:54 PM O Type here to search

Explanation / Answer

Revenue = -q^3 + 300q^2
Cost = 560 + 14q

So, profit P = R - C

P = -q^3 + 300q^2 - 14q - 560

Derivin' :

dP/dq = -3q^2 + 600q - 14 ------> ANS

Didnt work?
Try this

-30000q^2 + 60000q - 14

The unit is dollars per hundred units sold

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B)
To max profit, first do dP/dq = 0

-3q^2 + 600q - 14 = 0

3q^2 - 600q + 14 = 0

q = (600 +/- sqrt(360000-168)) / 6

q= 199.97 , 0.0233360561909260667

So, we have either
199.97 or 0.02
hundred units sold

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