Two ships, A and B, leave port at the same time. Ship A travels northwest at 22

Question

Two ships, A and B, leave port at the same time. Ship A travels northwest at 22 knots and ship B travels at 26 knots in a direction 42 Degree west of south. (1 knot = 1 nautical mile per hour; see Appendix D.) What are (a) the magnitude (in knots) and (b) direction (measured relative to east) of the velocity of ship A relative to B? (c) After how many hours will the ships be 160 nautical miles apart? (d) What will be the bearing of B (the direction of the position of B) relative to A at that time? (For your angles, takes east to be the positive x direction, and north of east to be a positive angle. The angles are measured from -180 degrees to 180 degrees. Round your angles to the nearest degree.)

Explanation / Answer

a) vy = -20*sin45 + 26*sin43 = 3.5898 **** vy = 20*cos45 + 26*cos43 = 33.157 ------------------------------------------------- magnitude = 33.3508 = 33.4 knots -------------------------------------------------------------------------------------------------- b) direction = arctan(y/x) = 83.8 degrees

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