Two satellites, one in geosynchronous orbit (T=24hrs) and one with a period of 1

Question

Two satellites, one in geosynchronous orbit (T=24hrs) and one with a period of 12 hrs, are orbiting Earth. How many times larger than the radius of the Earth is the distance between the orbits of the two satellites. (Mass of Earth= 5.98•10^24 kg), (G=6.67•10^-11 Nm^2), (g=9.81 m/s^2), (Radius of Earth= 6.38•10^6).
The answer is .51
I think im supposed to use the energy formula solve for both the radius's and compare but i was unable to reach the answer Two satellites, one in geosynchronous orbit (T=24hrs) and one with a period of 12 hrs, are orbiting Earth. How many times larger than the radius of the Earth is the distance between the orbits of the two satellites. (Mass of Earth= 5.98•10^24 kg), (G=6.67•10^-11 Nm^2), (g=9.81 m/s^2), (Radius of Earth= 6.38•10^6).
The answer is .51
I think im supposed to use the energy formula solve for both the radius's and compare but i was unable to reach the answer
The answer is .51
I think im supposed to use the energy formula solve for both the radius's and compare but i was unable to reach the answer

Explanation / Answer

The period of a satellite is the time it takes it to make one full orbit around an object.

T = 2*sqrt(R^3/GM)

T1 = 2R1*sqrt(R1^3/GM)

GM = 6.67•10^-11 * 5.98•10^24 = 3.988*10^14

24*60*60 = 2*sqrt(R1^3 / 3.988*10^14 )

R1 = 42.25*10^6 m

T2= 2R2*sqrt(R2/GM)

12*60*60 = 2*sqrt(R1^3 / 3.988*10^14 )

R2 = 26.61*10^6 m

R2 - R1 = 15.64*10^6 m

R2-R1 / Rearth = 15.64*10^6 / 6.38•10^6 = 2.45 times

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