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PLEASE ANSWER ONLY QUESTION 13 AND 14. Question 13: Based on your results above

ID: 134922 • Letter: P

Question

PLEASE ANSWER ONLY QUESTION 13 AND 14.

Question 13:

Based on your results above in Question 12, give the correct fitness relation for the genotypes in this population. (1 mark)

W11 = W12 > W22

W11 = W12 < W22

W11 > W12 > W22

W11 < W12 < W22

W11 < W12 > W22

W11 > W12 < W22

  

QUESTION 14

Question 14:

Based on your results above in Questions 12 and 13, give the most likely type of natural selection occurring in this population of sunflowers. (1 mark)

Directional selection against recessive allele A2 whereby A1 increases and A2 decreases.

Directional selection against dominant allele A1 whereby A2 increases and A1 decreases.

Directional selection against incompletely dominant allele A2 whereby A1 increases and A2 decreases.

Directional selection against incompletely dominant allele A1 whereby A2 increases and A1 decreases.

Overdominance whereby both alleles are maintained and a stable equilibrium is present.

Underdominance whereby an unstable equilibrium is present.

HERE IS INFORMATION YOU NEED FOR QUESTION 13 AND 14.

Question 12:

A recent field experiment examined how the genotype at one locus affected the survival of sunflowers. Survival was surveyed at the time of flowering for these 244 plants.

The following table shows the results of this experiment:

Genotype

A1A1

A1A2

A2A2

Number Surviving

52

170

22

Answer the following questions:

Round your answer to three decimal places and submit your answer in the correct format (e.g. 0.062).

(a) What are the relative fitness values (W) for each genotype?

(i) The fitness of genotype A1A1 = W11 = 0.306

(ii) The fitness of genotype A1A2 = W12 = 1.000

(iii) The fitness of genotype A2A2 = W22 = 0.129

(b) What are the selection coefficients (s) for each genotype?

(i) The selection coefficient of genotype A1A1 = s11 = 0.694

(ii) The selection coefficient of genotype A1A2 = s12 = 0.000

(iii) The selection coefficient of genotype A2A2 = s12 = 0.871

W11 = W12 > W22

W11 = W12 < W22

W11 > W12 > W22

W11 < W12 < W22

W11 < W12 > W22

W11 > W12 < W22

Explanation / Answer

Q 13 0.306<1.00>0.129

W11<W12>W22

Q 14Overdominance whereby both alleles are maintained and a stable equilibrium is present.

Q14

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