Part A After the system is released, find the horizontal tension in the wire. Su

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Part A

After the system is released, find the horizontal tension in the wire.

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Part B

After the system is released, find the vertical tension in the wire.

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Part C

After the system is released, find the acceleration of the box.

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Part D

After the system is released, find magnitude of the horizontal and vertical components of the force that the axle exerts on the pulley.

Express your answers separated by a comma.

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A 12.0-kg box resting on a horizontal, frictionless surface is attached to a 5.00-kg weight by a thin, light wire that passes without slippage over a frictionless pulley (the figure (Figure 1) ). The pulley has the shape of a uniform solid disk of mass 1.70 kg and diameter 0.520 m .

Part A

After the system is released, find the horizontal tension in the wire.

|Th| =   N  

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Part B

After the system is released, find the vertical tension in the wire.

|Tv| =   N  

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Part C

After the system is released, find the acceleration of the box.

a =   m/s2  

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Part D

After the system is released, find magnitude of the horizontal and vertical components of the force that the axle exerts on the pulley.

Express your answers separated by a comma.

Fx,Fy =   N  

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Explanation / Answer

on 5kg block,

5g - Tv = 5a .....(i)

on pulley ,

torque = r xF = I x alpha

r ( Tv - Th) = (mr^2 /2 ) (a/r)

Tv - Th = (1.70 a)/2

Tv - Th =0.85a ............(ii)

On 12 kg block,

Th = 12a .....(iii)

from (i), (ii) and (iii) ,

5g = ( 5 + 0.85 + 12)a

a = 2.75 m/s^2

A) Th = 12a = 12 x 2.75 = 32.97 N

B) Tv - Th = 0.85a

Tv = 0.85x2.75 + 32.97   = 35.31 N

C) a = 2.75 m/s^2

D) Fx = Th = 32.97 N

Fy = Tv + 1.70g =52 N

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