The answer is not zero for both.. Two particles collide, head-on. They have iden

Question

The answer is not zero for both..

Two particles collide, head-on. They have identical masses, and pre-collision speeds are equal. Their collision is completely elastic. Describe the particles' velocities after the collision. The magnitudes of the velocities are the same but the directions are reversed. One of the particles continues with the same velocity, and the other comes to rest. Both are zero. One of the particles continues with the o same velocity, and the other reverses direction at twice the speed. More information is required to determine the final velocities.

Explanation / Answer

here,

from Conservation of Momentum

m1v1 + m2v2 = m1v1' + m2v2

ATQ :

m1 = m2 = m
v1 = v2 = v

2v = v1' + v2'
v2' = v1' - 2v ------------------(1)

also from conservation of ENergy we have :

0.5m1*v1^2 + 0.5m2*v2^2 = 0.5m1*v1'^2 + 0.5m2*v2'^2
using consition in uestion we ahve

2v^2 = v1'^2 + v2'^2

using 1 we get

2v^2 = v1'^2 + (v1' - 2v)^2

v1' = v

eqn 1 become :

v2' = -v

Therefore option 1 is correct

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