The answer is D, please explain why. When cobalt chloride is added to pure water

Question

The answer is D, please explain why.

When cobalt chloride is added to pure water, the Co^2+ ions hydrate. The hydrated form then reacts with the Cl^- ions to set up the equilibrium shown here: Co(H_2O)_6^2^+ + 4Cl^- CoCl_4^2- + 6H_2O Which statement accurately describes the change that the system will undergo if water is added? a. The color will become more blue. b. The equilibrium will shift to the right. c. More water will be produced. d. More chloride ions will be produced. e. There will be less of the hydrated cobalt ion at the new equilibrium position.

Explanation / Answer

According to Le Chatelier, the shift goes toward counterbalancing the change in equilibrium

if we add water, then, we clearly:

dilute the system

favour moles of product, i.e the right side

a)

the color will NOT become blue, since more products are present, they will react to form more reactants, i.e pink

b )

False, equilibrium shifts toward reactants, i.e. left

c)

False, since we added water, then water will react to form more reactats, i.e. left side

d)

More pink color and Cl- ions will be produced, since the shift goes toward the left, so left side increases in concentration, this is TRUE

e)

false, the hydrate will increases, as stated previously

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