Questions 5-6 are based on the f these plants, the allele for red color flower s
ID: 134596 • Letter: Q
Question
Questions 5-6 are based on the f these plants, the allele for red color flower shows incomplete dominance over the allele for white flowers. This is very convenien homozygous dominant (CRCR red flowers). For your experiment, you produced a large number of plants, 25% had red flowers (CRCR), 25% had white flowers (CwCw) and 50% had pink flowers(CRCw). Calculate the allele frequency of this population, what is the value of p & q? You transplanted them into different habitats and left some in the lab (using the same proportions in all the habitats). You waited a few years, while plants reproduce for a few generations and then you go back and resample the populations you've transplanted. ollowing: Let's say you are studying a population of Japanese four o'clock plants. In t for this experiment because you can distinguish the heterozygous (CRCW pink flowers) from the In the lab, you ensured that all individuals receive all requirements to grow and reproduce and mate randomly. A) Is the lab population in Hardy-Weinberg equilibrium? Yes/No, explain B) If the population is in Hardy-Weinberg equilibrium, what do you expect the distribution of the phenotypes after a few generations breeding in the lab? C) Calculate the value of p and q 6. In habitat A, you find that half of the population have red flowering plants (CRCR), and the other half have white flowering plants (CWcW) but there are no pink flowering plants (CRcW), A) What is the value for p and q in this population? B) Is the population in habitat A in Hardy-Weinberg equilibrium? Yes/No, explain. C) Which one(s) of the five agents of evolutionary change could be responsible for these results? Explain. D) What type(s) of selection (stabilizing, disruptive, directional, oscillating, etc...) could be responsible for the results in habitat A? Explain.Explanation / Answer
According with Hardy-Weinberg equation:
p2 + 2pq + q2 = 1 and p + q = 1
p = frequency of the dominant allele in the population
q = frequency of the recessive allele in the population
p2 = percentage of homozygous dominant individuals
q2 = percentage of homozygous recessive individuals
2pq = percentage of heterozygous individuals
What is the value of p and q?
P2=0.25, q2=0.25 so p=0.5 q=O.5
5A) Yes the lab population is in Hardy-Weinberg equilibrium because they were crop under controlled conditions (no migration, mate randomly, no natural selection, no mutations, large population because you expected years for resampling) so we can say that no evolutionary forces acted in this population and is close to the Hardy-Weinberg equilibrium.
5B) That they don’t change, in other words, the frequency of the phenotypes will stay constant like a reflect of the same allele frequency at genotypic level.
5C) p and q will stay at the same values of p=0.5 and q=O.5 due to the population is in Hardy-Weinberg equilibrium.
6A. P2=0.50, q2=0.50 so p=0.71 and q=O.71
6B. The population isn’t in H-W equilibrium because the heterozygotes alleles have disappeared.
6C. Probably genetic drift or some kind of selection because the heterozygotes have disappeared.
6D. Disruptive selection because only survived the homozygotes, probably there was a negative selection again the pink flowers heterozygote plants.
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