Two blocks with different mass are attached to either end of a light rope that p

Question

Two blocks with different mass are attached to either end of a light rope that passes over a light, frictionless pulley that is suspended from the ceiling. The masses are released from rest, and the more massive one starts to descend. After this block has descended a distance 1.00 m , its speed is 2.50 m/s .

Part A

If the total mass of the two blocks is 18.0 kg , what is the mass of the more massive block?

Take free fall acceleration to be 9.80 m/s2 .

m1= (in Kg)

Part B

What is the mass of the lighter block?

Take free fall acceleration to be 9.80 m/s2 .

m2= (in Kg)

Explanation / Answer

given

m1 + m2 = 18 kg

Apply conservation of energy

gain in kinetic energy = loss of potentail energy

0.5*(m1+m2)*v^2 = (m2 - m1)*g*h

0.5*18*2.5^2 = (m2-m1)*9.8*1

56.25 = (m2-m1)*9.8

m2 - m1 = 5.74 kg

(18 - m1) - m1 = 5.74

18 - 2*m1 = 5.74

m1 = (18 - 5.74)/2

= 6.13 kg

so, m2 = 18 - 6.13

= 11.87 kg

so,

mas of more massive block = 11.87 kg <<<<<-------Answer

mass of the lighter block = 6.13 kg <<<<<-------Answer

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