A projectile is fired from ground level at an angle of 52 above the horizontal w

Question

A projectile is fired from ground level at an angle of 52 above the horizontal with an initial speed of 34 m/s .A) What is the magnitude of its instantaneous velocity at the moment it is fired? B) What is the direction (relative to horizontal) of its instantaneous velocity at the moment it is fired? C) What is the magnitude of its instantaneous velocity the moment it reaches its maximum height? D) What is the direction (relative to horizontal) of its instantaneous velocity the moment it reaches its maximum height? E) What is the magnitude of its instantaneous velocity the moment before it hits the ground? F) What is the direction (relative to horizontal) of its instantaneous velocity the moment before it hits the ground?

Explanation / Answer

here,

initial speed of the projectile , v = 34 m/s

angle with the horizontal , theta = 52 degree

A)

the magnitude of its instantaneous velocity at the moment it is fired is 34 m/s

B)

the direction (relative to horizontal) of its instantaneous velocity at the moment it is fired is 52 degree counterclockwise

C)

when it reaches the maximum height its y component of velocity is zero

vx = v * cos(theta)

vx = 20.93 m/s

the magnitude of its instantaneous velocity the moment it reaches its maximum height is 20.93 m/s

D)

as at the maxximum height

the vertical velocity is zero

the direction (relative to horizontal) of its instantaneous velocity the moment it reaches its maximum height is in the horizontal direction

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