A parallel plate capacitor is made by using two parallel plates, each of area 2.

Question

A parallel plate capacitor is made by using two parallel plates, each of area 2. 0 m^2. The plates are separated by 4. 0 mm as shown in the figure. The capacitor is charged by putting Q = 1. 0 mu C of charge on one plate and -1. 0 mu C of charge on the other. The charges are distributed uniformly over the surface of the plates. Why do charges reside at the inner surface of each plate? What are the charge densities of plates? What is the electric field strength inside the parallel plate capacitor? What is the direction of electric field at the center of the capacitor? Draw an arrow inside the capacitor to indicate direction. Show that the electric field strength outside the capacitor is zero. Will the electric field strength increase, decrease or remain constant if the separation between the plates is doubled? Explain. Assume that you release an electron from rest at the center of the capacitor. Describe the subsequent motion of the electron after it is released. Calculate the speed of the electron as it reaches one of the plates.

Explanation / Answer

a)because equal and opposite charges are applying on two plates

b)0.5*10-6c/cm2 and -0.5*10-6c/cm2

c)5.64*104N/C

d)

e)According to Gauss law the total normal flux is equal to the charge anside it but there is no charge at outside so electric field is zero at outside of capacitor

f)Electric field sterngth is decreasea as distance is doubled because electric field is inversely proportional to distance between plates

g)The electron moves towards positive plate capacitor and when an eletron moves it gains kinetic energy so kinetec energy is equal to energy in capacitor so velocity of eletron is 34.6*1013m/sec

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