The brochure advertising a sports car states that the car can be moving at 100.0

Question

The brochure advertising a sports car states that the car can be moving at 100.0 km/h, and stop in 37.19 meters. What is its average acceleration during a stop from that velocity? Express your answer in m/s2. Consider the car's initial velocity to be a positive quantity The brochure advertising a sports car states that the car can be moving at 100.0 km/h, and stop in 37.19 meters. What is its average acceleration during a stop from that velocity? Express your answer in m/s2. Consider the car's initial velocity to be a positive quantity

Explanation / Answer

given,

speed = 100 km/h or 27.7778 m/s

distance = 37.19 m

v^2 = u^2 + 2as

0 = 27.7778^2 + 2 * a * 37.19

a = 10.374 m/s^2

average acceleration = 10.374 m/s^2

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