A 51 kg skier encounters a dip in the snow\'s surface that has a circular cross

Question

A 51 kg skier encounters a dip in the snow's surface that has a circular cross section with a radius of curvature of 12 m.

Part A

If the skier's speed at point A in the figure is 7.5 m/s , what is the normal force exerted by the snow on the skier at point B? Ignore frictional forces.(Figure 1)

Express your answer using two significant figures.

111

Figure 1 of 1

A 51 kg skier encounters a dip in the snow's surface that has a circular cross section with a radius of curvature of 12 m.

Part A

If the skier's speed at point A in the figure is 7.5 m/s , what is the normal force exerted by the snow on the skier at point B? Ignore frictional forces.(Figure 1)

Express your answer using two significant figures.

111

Figure 1 of 1

Explanation / Answer

from the conservation of energy

del KE = del PE

1/2 m ( vf^2 - vi^2) = mgh

vf ^2 = 2gh + vi^2

The centripetal acceleration is

     a = Vf2 / r= ( 2gh + Vi2 ) / r

normal force exerted by the snow on the skier at pointB

N = m (g + a)

= m ( g + [ ( 2gh +Vi2 ) / r ] )

=51 ( 9.8 + ( 2 (9.8) (1.75) +(7.5)^2/12

=884.63 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.