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1. (3 points) What is the effect of the magnetic field on the particle below? A.

ID: 1339420 • Letter: 1

Question

1. (3 points) What is the effect of the magnetic field on the particle below? A. The particle will speed up B. The particle will slow down C. The particle will curve to the left D. The particle will curve to the right E. The field will have no effect 2. (3 points) The loop of wire has a current going in the counterclockwise direction when viewed from above. Which of the pictured stationary magnets has field lines that most closely resemble the ones surrounding the loop? A) B) C)D) E) 3. (3 points) What direction is the magnetic field at the indicated point? A.B./ C. D. into page E. out of page B? 21 4. (3 points) A Cu ion is fired into a uniform magnetic field with a velocity e. It is observed that the ion curves into a path with radius R. Now a Cu+ ion is fired along the same path with the same velocity. Neglecting the mass of the missing electron, what radius would be expected for the path of the second ion? A. R/4 B. R/2 C. R D. 2R E. AR

Explanation / Answer

1. C) The particle will curve to left. The direction of force will be given by v X B, which is to the left, so it curves left.

2. The anticlockwise current (as viewed from top) will cause a magnetic field going bottom to top inside the loop, which is equivalent to south-north inside a bar magnet. So the figure C is correct.

3) Direction of magnetic field is given by the direction of curl of right hand fingers as the thumb points to the direction of current, This is into the plain pf paper for both the wires. Hence the direction of magnetic field is into the page.

4) F = qvB

F = mv2/R

=> R = mv/qB

So for same m,v and B. Doubling the charge reduces radius by half

So answer. B) R/2

5. The inward flux is increasing with time. So the induced current should be such that it increase the outward flux, hence anticlockwise current is induced

6. Electron beam will bend least in case C since the magnetic field in the region of direction of electron flow is parallel to electron flow in case C

7. F =qVXB. so the direction of V X B gives the direction of force. Since it is undergoing circular motion, the magnetic force should be acting towards the center of the circle, which is true when magnetic field is up for both protons and antiprotons