The 20.0 cm by 35.0 cm rectangular circuit shown in the figure (Figure 1) is hin
ID: 1339414 • Letter: T
Question
The 20.0 cm by 35.0 cm rectangular circuit shown in the figure (Figure 1) is hinged along side ab. It carries a clockwise I = 5.40 A current and is located in a uniform 1.50 T magnetic field oriented perpendicular to two of its sides, as shown.
Which force exerts a torque about the hinge ab?
ab, bc, cd, or da
Calculate only the force that exert the torque mentioned in part A.
F = ____________ N
Use your results from part B to calculate the torque that the magnetic field exerts on the circuit about the hinge axis ab.
T = ____________ N * mExplanation / Answer
force due to wire cd exerts a torque about the hinge ab
force = I(L B sin theta) , theta =90
=I(L B)=5.40A * 0.2m * 1.5T=1.62N
torque= r F sin theta due to wire ab torque =0 because r=0
r=0.35m from cd , F=1.62N due to cd , theta =90 between r and F
torque=0.57Nm
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