An electron enters a homogeneous magnetic field pointing out of the paper. Of th

Question

An electron enters a homogeneous magnetic field pointing out of the paper. Of the indicated trajectories, which one is the most likely? Explain (in the space next to the figure). The figure shows a positive charge in a large homogeneous field pointing out of the paper. If the field is an electric field, and the charge is moving north, what is the direction of the force? If the field is a magnetic field, and the charge is moving north, what is the direction of the force? If the field is 9 mT, the mass of the particle is 27 Times 10^-9 kg, its initial speed 7.9 m/s moving north, and its charge 6 muC, what is the magnitude and direction of its acceleration?

Explanation / Answer

F= q*(VxB)
So, direction of deflection will be given by cross product of V and B multiplies by sign of q
Here:
B: pointing outward
V: upward
VxB = right
But q is negative
so force will acts towards left
SO electron will bend to right and follow a counter clockwise path
Answer: B

2.
a)
F=Q*E
force is in direction of electric field
Answer: F. out of the papaer

b)
F= q*(VxB)
So, direction of deflection will be given by cross product of V and B multiplies by sign of q
Here:
B: pointing outward
V: north
VxB = east
But q is positive
so force will acts towards east
Answer: B

c)
Direction is towards east
a = q*(VxB) /m
= (6*10^-6)*(7.9*9*10^-3)/ (27*10^-9)
=15.8 m/s^2

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.