An arm is holding a 50 N hammer in equilibrium as shown in the picture. The bice

Question

An arm is holding a 50 N hammer in equilibrium as shown in the picture. The bicep attaches to the forearm 3 cm from the elbow joint, and the hammer is held 35 cm from the elbow joint. Ignore the weight of hoots and muscles in this problem. Find the upward force F the bicep exerts on the forearm bone. Find the downward force N the elbow joint exerts on the forearm bone. How do these forces compare to the weight of the hammer? Using your answer to (b), calculate the torque around the bicep attachment point.

Explanation / Answer

under equlibrium condition the net torque is zero

Torque = 0

F( 0.03 m) - mg ( 0.35 m) = 0

F = mg ( 0.35 m)/0.03 m

= 50 N( 0.35)/ 0.03 )

=583.33 N

(b)

N+ mg = F

N = F - mg = 583.33 N - 50 N = 533.33 N

(c)

F/ W = 583.33/50 N = 11.66

F/N - 533.33/50 N = 10.66

(d)

torque = rF = 533.33 ( 0.35 m) = 186.66 N m

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