1) A projectile is launched at angle of 45 degrees with a velocity of 250 m/s. T

Question

1)
A projectile is launched at angle of 45 degrees with a velocity of 250 m/s. The magnitude of the horizontal velocity of the projectile at the time it reaches maximum altitude is?

2)
A projectile is launched with a velocity of 25 m/s from the top of a 75m height. How many seconds will the projectile tale to reach the bottom?

3)
An object is launched from the ground with an initial velocity and angle such that the maximum height achieved is equal to the total range of the projectile. The tangent of the launch angle is?

1)
A projectile is launched at angle of 45 degrees with a velocity of 250 m/s. The magnitude of the horizontal velocity of the projectile at the time it reaches maximum altitude is?

2)
A projectile is launched with a velocity of 25 m/s from the top of a 75m height. How many seconds will the projectile tale to reach the bottom?

3)
An object is launched from the ground with an initial velocity and angle such that the maximum height achieved is equal to the total range of the projectile. The tangent of the launch angle is?


A projectile is launched at angle of 45 degrees with a velocity of 250 m/s. The magnitude of the horizontal velocity of the projectile at the time it reaches maximum altitude is?

2)
A projectile is launched with a velocity of 25 m/s from the top of a 75m height. How many seconds will the projectile tale to reach the bottom?

3)
An object is launched from the ground with an initial velocity and angle such that the maximum height achieved is equal to the total range of the projectile. The tangent of the launch angle is?

Explanation / Answer

1) horizontal velocity doesn't change as there is no acc. in horizonatl direction.

so ux = ucos45 = 250 x cos45 =176.78 m/s

2) PLease specify direction of launching velocity , Its needed.

(use this equation h = ut - gt^2 /2 )

3) max. height = v^2 sin^ (@) / 2g

Range = v^2 sin2@ / g

Given max. height = Range

v^2 sin^ (@) / 2g = v^2 sin2@ / g

sin^2 @ = 2 sin2@

sin@ . sin@ = 2 ( 2 sin@ cos@)

sin@ = 4 cos@

tan@ = 4

@ =75.96 degrees

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