A bar magnet induces a current in an N -turn coil as the magnet moves closer to

Question

A bar magnet induces a current in an N-turn coil as the magnet moves closer to it as shown in (Figure 1) . The coil's radius is R m, and the average induced emf across the bulb during the time interval is V.

Part A

Find the rate of change of magnetic field.

Express your answer in terms of the variables , N, R, and appropriate constants.

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Part B

Determine the induced current. Assume that R0 is the resistance of the coil.

Express your answer in terms of some or all of the variables , N, R, R0.

2RR0

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Part C

Is the direction of the induced current from lead a to b, or from b to a?

Is the direction of the induced current from lead a to b, or from b to a?

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Figure 1 of 1

Explanation / Answer

partA

flux = N*B*A

emf is defined as the rate ofchange in flux

emef = e = (d/dt)*N*B*A

emf = (dB/dt)*N*A

dB/dt = e/NA = e/N*pi*R^2

part(B)

i = e/Ro = e/N*pi*R^2*Ro

part(c)

from lenz law rhe ems opposes the rate of chenge in flux

here the flux is increasing in upwards ,the current flows from ato b to decrease the flux

from a to b

from a to b

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