this point will be in the region y < 0. this point will be in the region 0 < y <

Question

this point will be in the region y < 0. this point will be in the region 0 < y < 4.50 mm.     this point will be at y = 4.50 mm (halfway between the q1 and q2).    this point will be in the region 4.50 mm < y < 9.00 mm.    this point will be in the region 9.00 mm < y

c. What will be the y-coordinate of this point?______mm
d. How would the y-coordinate you found in part c change if q3 had a different value? choose from below.

it would be the same if q3 was -16.7 nC, but different for any other value of q3.    it would be the same if q3 is positive, but different if q3 is negative.     it would be the same if q3 is negative, but different if q3 is positive.    it would be different for any other value of q3.    it would be the same regardless of q3's value

Explanation / Answer

part a )

x = 0 mm it should on the same line

part b )

this point will be in the region 0 < y < 4.50 mm.

reason : It can't be higher than q1 or lower than q2 because it would be repelled, so it must be between q1 and q2.
it can't be closer to q or exactly halfway because it would be repelled

part c )

kxq1xq3 / (r - y)^2 = k x q2 x q3 / y^2

q1 / (r - y)^2 = q2 / y^2

q1x y^2 = q2 x (r - y)^2

q1 x y^2 = q2×(r^2 - 2 x r x y + y^2)

(q1 - q2)x y^2 + q2 x 2 x r x y - q2xr^2 = 0

(10.8 - 6.6) *y² + 6.6 x 2 x 9 x y - 6.6 x 9^2 = 0

4.2y^2 + 118.8 y - 534.6

y = 3.95 , -32.23

negative answer is not possible

y = 3.95 mm

part d )

it would be the same regardless of q3's value

here you can see

q1 / (r - y)^2 = q2 / y^2 q3 is not matter

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.