I a confused onw whether this should be treated as a dipole or two point charges
ID: 1330133 • Letter: I
Question
I a confused onw whether this should be treated as a dipole or two point charges in an electric field. I see to not be deriving part B and part D correctly. Can you please explain in details and show the work. Thank you!3. Two particles are fixed on an x axis. Particle I of charge q is located at x ta. Particle 2 of charge-q is located at x-. Consider a point P is located along they axis at y = +d. For each part assume that the following variables are given: adg and phssical constants What is the direction of the electric field at point P? Express your answer using unit vectors. a. Ener -1 b. What is the magnitude of the electric field at point P x: -a X1 qa
Explanation / Answer
Charge 1 :- q @ x= +a
Charge 2 :- -q @ x =-a
PART B.)
Electric field at point P -
E = k*q/r^2 * sin() + k*q/r^2 * sin()
E = 2 k*q/r^2 * sin()
Where,
r = sqrt(a^2 +d^2)
sin() = a/sqrt(a^2 + d^2)
E = (2kq/(a^2 +d^2) ) * (a/sqrt(a^2 + d^2))
E = 2kaq/ (a^2 + d^2)3/2
Magnitude of Electric Field @ P, E = 2kaq/ (a^2 + d^2)3/2
PART D)
Charge q3 = 2q
Electric Force, F = q3*E
F = 2q * 2kaq/ (a^2 + d^2)3/2
k = 1/(4Eo)
F = q^2 *a / (Eo (a^2 + d^2)3/2)
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