For KVL... I thought to assign the sign of the voltage is based on voltage rise

Question

For KVL... I thought to assign the sign of the voltage is based on voltage rise and drop. So it's 10-2Ix, however why are they assuming -3Ix ?? I thought current goes from positive to negative voltage signs. So if Ix is going south, doesn't that mean the voltage is rising? I'm confused Problem (1) (20 points) For the circuit shown, 21, Find the current I, The power of each element and define whether it is absorbing or supplying power KVL: 10-(21,)-(3)(L)-0 Pov =-(10)(1.) 10-(21,)-(30,)-02 ,' = 2A Pav = 20W(delivered) Bu, = 8W (absorbed ) Po-12W(absorbed) 1-(21,) Pa (3(4.)

Explanation / Answer

Conventionally Electric current flows from Higher to Lower potential ,Here Ix is the current flowing in the loop ,which is flowing in opposite direction of 10 V .So by Applying KVL we get

10-2Ix-3Ix=0

5Ix=10

Ix=2 A

a)

P10 V =-10*2 =-20 W

So 20 W delivered

b)

P2ix =(2Ix)(Ix) =2*2*2 =8 Watts(absorbed)

c)

P3=I2R=3*22=12 Watts (absorbed)

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