A 15-gram rubber ball is released from a height of 8 meters above a flat surface

Question

A 15-gram rubber ball is released from a height of 8 meters above a flat surface on the moon. Gravitational acceleration on the moon is 1.62 meters per second squared. Assume that no energy is lost from frictional drag. What is the velocity, in units of meters per second, of the rubber ball the instant before it strikes the flat surface? Click the icon to view the types of energy. Click the icon to view the table of common derived units in the SI system. The velocity of the rubber ball the instant before it strikes the flat surface is (Round your answer to two significant digits.)

Explanation / Answer

ball is releasing so initial velocity = 0

using 3rd equation of motion

v^2 = u^2 + 2gh

v = sqrt(2gh)

here g= 1.62 m/s^2 ;

h = 8 m

v = sqrt(2 * 1.62 * 8 )

v = sqrt(25.92)

v = 5.09 = 5.1 m/s

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