A gymnast of mass 50.0 kg hangs from a vertical rope attached to the ceiling. Yo

Question

A gymnast of mass 50.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume that the rope does not stretch. Use the value 9.81m/s2 for the acceleration of gravity.

Part A

What force is applied to the driver by his seat belt during that fraction of a second?

Express your answer using two significant figures.

I ALSO DID TRY

13407.654

13407

13407.65

13407.7

13407.82

13407.69

ery close. Check the rounding and number of significant figures in your final answer.

Explanation / Answer

A gymnast of mass 50.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume that the rope does not stretch.

1) tension T in the rope if the gymnast climbs up the rope with an upward acceleration of magnitude 0.600 m/s^2
2) tension T in the rope if the gymnast slides down the rope with a downward acceleration of magnitude 0.600 m/s^2

solution :  assuming g is acceleration due to gravity (in m/s/s) then
1) 50*(g+0.6)
2) 50*(g-0.6)

part A

21m/s ÷ 0.13s = 161.54 m/s² = a
F = ma = 83Kg x 161.54 m/s² = 13407.82 N
Express your answer using two significant figures.
F = 13000 N

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