After being disconnected from the battery, inserting a dielectric with will decr

Question

After being disconnected from the battery, inserting a dielectric with will decrease V.A parallel plate capacitor with plate separation d is connected to a battery. The capacitor is fully charged to Q Coulombs and a voltage of V. (C is the capacitance and U is the stored energy.) Answer the following questions regarding the capacitor charged by a battery. For each statement below, select True or False.

After being disconnected from the battery, inserting a dielectric with will decrease U.

After being disconnected from the battery, inserting a dielectric with will decrease V.

After being disconnected from the battery, increasing d increases V.

With the capacitor connected to the battery, decreasing d increases C.

With the capacitor connected to the battery, inserting a dielectric with will decrease C.

With the capacitor connected to the battery, decreasing d increases U.

Explanation / Answer

After being disconnected from the battery, inserting a dielectric with will decrease U...TRUE

Unew = U/K

After being disconnected from the battery, inserting a dielectric with will decrease V....TRUE

vNEW = v/K

After being disconnected from the battery, increasing d increases V.....TRUE

With the capacitor connected to the battery, decreasing d increases C...TRUE

C = eo*A/d

With the capacitor connected to the battery, inserting a dielectric with will decrease C...False

Unew =k*U

With the capacitor connected to the battery, decreasing d increases U....TRUE

C increases then U increases by using U = 0.5*C*V^2

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