Multiple-Choice Homework Problem 5.1 A positively charged particle moves through

Question

Multiple-Choice Homework Problem 5.1 A positively charged particle moves through an electric field. As part of a complicated trajectory, the particle passes through the points A and B. The electric potential of the two points is such that VB > VA. The electric force is the only force acting on the particle. What can be deduced about the speed, v, of the particle at the two points?

(a) The speed is equal at the two points.

(b) The speed is larger at A than at B.

(c) The speed is larger at B than at A.

Explanation / Answer

it is given that Vb>Va

so the potential energy of particle at B is greater than A. But according tolaw of conservation of energy the total energy is constant at all the places

KE+PE= constant

Hence the Kinetic energy of particle at A is greater than B. So the particle is moving with a greater velocity at A than B

So option (b) is correct.

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