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A cylinder with a piston contains 0.200 mol of nitrogen at 1.70×10 5 Pa and 320

ID: 1326745 • Letter: A

Question

A cylinder with a piston contains 0.200 mol of nitrogen at 1.70×105 Pa and 320 K . The nitrogen may be treated as an ideal gas. The gas is first compressed isobarically to half its original volume. It then expands adiabatically back to its original volume, and finally it is heated isochorically to its original pressure.

Need part H and I. it is not 50.5 J

Part A

Find the work done by the gas during the initial compression.

-266

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Correct

Part B

Find the heat added to the gas during the initial compression.

-930

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Correct

Part C

Find internal-energy change of the gas during the initial compression.

-664

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Correct

Part D

Find the work done by the gas during the adiabatic expansion.

Enter your answers numerically separated by commas.

161

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Correct

Part E

Find the heat added to the gas during the adiabatic expansion.

0

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Correct

Part F

Find the internal-energy change of the gas during the adiabatic expansion.

-161

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Correct

Part G

Find the work done by the gas during the final heating.

0

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Correct

Part H

Find the heat added to the gas during the final heating.

?

Incorrect; Try Again; 5 attempts remaining

Part I

Find the internal-energy change of the gas during the final heating.

?

W =

-266

  J  

Explanation / Answer

A) W1 = -266 J

B) Q1 = -930 J

C) delta_U1 = -664 J

D) W2 = +161 J

E) Q2 = 0

F) delta_U2 = -161 J

G) W3 = 0

H) let Q3 is the heat added to the system.

In the whole process there is no net change in internal energy

because Internal energy is a state function.

dU = dU1 + dU2 + dU3

0 = dU1 + dU2 + dU3

==> dU3 = -dU1 - dU2

= 664 + 161

= 825 J

so, when heat is added at constanr volume, workdone W3 = 0


so, dQ3 = dU3 + dW3

dQ3 = dU3

= 825 J <<<<-----Answer

I) dU3 = 825 J <<<<-----Answer

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