1. A thin, metallic, spherical shell of radius a = 6.0 cm has a charge q a = 5.0

Question

1. A thin, metallic, spherical shell of radius a = 6.0 cm has a charge qa = 5.00×10-6 C. Concentric with it is another thin, metallic, spherical shell of radius b = 12.60 cm and charge qb = 6.00×10-6 C. Find the electric field at radial points r where r = 0.0 cm.

2. Find the electric field at radial points r where r = 9.3 cm.

3. Find the electric field at radial points r where r = 18.9 cm.

4. Discuss the criterion one would use to determine how the charges are distributed on the inner and outer surface of the shells. What is the charge on the outer surface of the outer shell?

Explanation / Answer

Use equation

E= Qenclosed/(40r2)

1) For r= 0.0cm, Qenclosed =0 C, hence E=0 N/C

2) For r= 9.3cm, Qenclosed =5*10^-6 C, hence E= Qenclosed/(40r2) = (9*10^9*5*10^-6)/0.093^2 = 5.2*10^6 N/C

3) For r= 18.9cm, Qenclosed =11*10^-6 C, hence E= Qenclosed/(40r2) = (9*10^9*11*10^-6)/0.189^2 = 2.77*10^6 N/C

4) All charge is distributed on the outer surface of the shell. So outer surface of inner shell will have total positive charge qa. Due to which a negative charge will be induced on the inner surface of outer shell and its outer surface will have positive charge qb.

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