1. A survey was conducted to determine the proportion of cat owners who vaccinat

Q: 1. A survey was conducted to determine the proportion of cat owners who vaccinat

Result: Answer note: 1 B 2 C 3 A P=0.0001, n=5000,np=0.5 4 D we need P(B) 5 D Approximately normal, sd =s/sqrt(n) 6 B 7 A By definition 8 A 9 D 10 A np=2000*0.12=240, sd=sqrt(2000*0.12*0.88) 11 D 0.64+0.21-0.68 12 C Answer note: 1 B 2 C 3 A P=0.0001, n=5000,np=0.5 4 D we need P(B) 5 D Approximately normal, sd =s/sqrt(n) 6 B 7 A By definition 8 A 9 D 10 A np=2000*0.12=240, sd=sqrt(2000*0.12*0.88) 11 D 0.64+0.21-0.68 12 C

ID: 3357159 • Letter: 1

Question

1. A survey was conducted to determine the proportion of cat owners who vaccinate their on a yearly basis. Based on the response of 200 cat owners a 90% confidence interval was calculated to be (0.57, 0.68). What can be concluded? A. We know that the true proportion of the cat owners who vaccinate their pets is B. we are 90% confident that between 57% and 68% of the cat owners vaccinate C. we are 90% confident that the sample proportion of cat owners who vaccinate D. 90% of the cat owners vaccinate their pets annually between 0.57 and 0.68. their pets annually their pets is between 0.57 and 0.68 Answer An experiment is set up in which tomato plants are placed into groups by color and then randomly asigned to fertilizer treatments. This is an example of which type of design? 2. A. Simple Random Sample. B. Matched pairs. C. Block design. D. None of the above. Answer 3. About 1 in 10,000 people are born with hemophilia A. We randomly select 5,000 newborn babies. Let success be that a baby has hemophilia A. Can we use the normal approximation to estimate the probability that exactly two have hemophilia A? A. No, because np is too small. B. Yes, because n is very large C. Yes, because nel-p) is greater than 10. D. No, because 5,000 are less than 10% of the babies that are born every year. Answer 4. P(A) 0.32, P(B A) 0.10, if A and B are dependent, what is PfA B? A. 0.032 B. 0.32 C. 0.3125 We cannot calculate this probability using the given information Answer Total

Explanation / Answer

Result:

Answer

note:

P=0.0001, n=5000,np=0.5

we need P(B)

Approximately normal, sd =s/sqrt(n)

By definition

np=2000*0.12=240, sd=sqrt(2000*0.12*0.88)

0.64+0.21-0.68