A lamp which is 7.5 cm tall is 68.0 cm in front of a converging lens which has a

Question

A lamp which is 7.5 cm tall is 68.0 cm in front of a converging lens which has a focal length of 40.0 cm.
(a) What is the image distance for this lamp and lens combination (include sign if negative)? ____cm
(b) If a screen is placed at the image location found in (a), what will be observed on the screen?

a clear, upright, virtual image is visible. a clear, inverted, real image is visible. a clear, upright, real image is visible. no image is visible on the screen. a clear, inverted, virtual image is visible

(c) If the screen is moved slightly farther from the lens than the distance found in (a), what will be observed on the screen?

a fuzzy image is visible. a clear image slightly larger than the original image is visible. a clear image slightly smaller than the original image is visible. no image is visible on the screen

Explanation / Answer

A)

Given that object distance is u = 68 cm

focal length f = 40 cm

then image distance is v = ?

apply lens formula

(1/u)+(1/v) = (1/f)

1/v = (1/40)-(1/68)

v = (68*40)/(68-40) = 97.14 cm

B) a clear,inverted ,real image is visible

C) fuzzy image isvisible

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