A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as

Question

A golf ball is hit off a tee at the edge of a cliff. Its x and y coordinates as functions of time are given by x = 16 are in meters and t is in seconds. and y = 3.72 4.90r, where x and y (a) Write a vector expression for the ball's position as a function of time, using the unit vectors i and j. (Give the answer in terms of t.) By taking derivatives, do the following. (Give the answers in terms of t.) (b) obtain the expression for the velocity vector V as a function of time m/s (c) obtain the expression for the acceleration vector a as a function of time m/s2 (d) Next use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the golf ball at t2.91 s. v= m/s m/s2

Explanation / Answer

a)
r = 16.6 t i + (3.72 t -4.9 t^2 ) j
b)
v = dr/dt
= 16.6 i + (3.72 - 2*4.9t) j
= 16.6 i + (3.72 - 9.8t) j
c)
a = dv/dt
= -9.8 j

d)
r = 16.6 t i + (3.72 t -4.9 t^2 ) j
= 16.6 *2.91 i + (3.72 *2.91 -4.9 (2.91)^2 ) j
= 48.31 i - 30.67 j

v = 16.6 i + (3.72 - 9.8t) j
= 16.6 i + (3.72 - 9.8*2.91) j
=16.6 i -24.8 j

a = -9.8 j

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.