Describe the change in the magnetic field in the interior of a solenoid carrying

Question

Describe the change in the magnetic field in the interior of a solenoid carrying a steady current I for the following two cases.

Case a) The length of the solenoid is doubled but the number of turns remains the same

1. the magnetic field is cut in half.

2. the magnetic field is cut to a quarter.

3. the magnetic field is quadrupled.

4. the magnetic field does not change.

5. the magnetic field is doubled.

Case b) The number of turns is doubled but the length remains the same.

1. the magnetic field does not change.

2. the magnetic field is doubled.

3. the magnetic field is quadrupled.

4. the magnetic field is cut to a quarter.

5. the magnetic field is cut in half.

Explanation / Answer

Magnetic field of a solenoid is given by

B=uo*N*I/L

a)

1. the magnetic field is cut in half.

from above equation magnetic field is inversly proportional to length , if Length is doubled ,then magnetic field of solenoid is cut in half.

b)

2. the magnetic field is doubled.

from above equation magnetic field is directly proportional to Number of turns , if Number of turns are doubled ,then magnetic field of solenoid is doubled.

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