A proton is acted on by a uniform electric field of magnitude 293 N/C pointing i

Question

A proton is acted on by a uniform electric field of magnitude 293 N/C pointing in the negative z direction. The particle is initially at rest. (a)In what direction will the charge move? z direction (b) Determine the work done by the electric field when the particle has moved through a distance of 2.55 cm from its initial position. How is work done defined in terms of the displacement and electric field vectors? Did you consider the angle between these two vect (c) Determine the change in electric potential energy of the charged particle. Consider the definition of change in electric potential energy in terms of the work done by the electric field. J (d) Determine the speed of the charged particle. Consider applying the conservation of energy principle. m/s

Explanation / Answer

A. - Z direction

B. Charge on proton = 1.60217657

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