The concepts in this problem are similar to those in Multiple-Concept Example 4,

Question

The concepts in this problem are similar to those in Multiple-Concept Example 4, except that the force doing the work in this problem is the tension in the cable. A rescue helicopter lifts a 71.0-kg person straight up by means of a cable. The person has an upward acceleration of 0.559 m/s2 and is lifted from rest through a distance of 11.3 m. (a) What is the tension in the cable? How much work is done by (b) the tension in the cable and (c) the person's weight? (d) Use the work-energy theorem and find the final speed of the person.

Explanation / Answer

F = m a = 71 * 0.559 = 39.69 N.

a) upward force F = T - F g

The person's weight = mg = 9.8 * 71 kg = 695.8 N.

Tension in the cable must then be 735.5 N

---------------------------------------------------------

b) W = F * d =735.5 N * 11.3 m

= 8311 J

---------------------------------------------------------

c) W = F * d = -695.8 N * 11.3 m

= -7863 J

--------------------------------------------------------

d) delta E = 1/2 m (delta v2)

delta v = sqrt (2 delta E / m) = sqrt (2 * 448 J / 71 kg)

= 3.55 m/s.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.