A conducting rod of mass 19 g and length 55 cm has holes drilled near each end s

Question

A conducting rod of mass 19 g and length 55 cm has holes drilled near each end so that it is free to slide in a vertical direction along two conducting rails as shown in the figure below. A current of 150 A is made to flow through an identical rod at the bottom of the assembly and return through the sliding sliding rod. (Notice the placement of an insulator.) Determine the height of the sliding rod above the base rod when in equilibrium. Assume the horizontal rods are very long.

A long, straight wire carries a current of 7.5 A. What is the magnitude of the magnetic field at a distance of 14 cm from the wire?

Explanation / Answer

Part A)

The weight must be balanced by the magnetic force...

F = uIIL/(2pi)(r) = mg

(4pi X 10-7)(150)(150)(.55)/(2pi)(r) = .019(9.8)

r = .0133 m

That is 1.33 cm

Part B)

B = uI/2pir

B = (4pi X 10-7)(7.5)/(2pi)(.14)

B = 1.07 X 10-5 T

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