A collision occurs between a 2.43 kg particle traveling with velocity Upper V Ov

Question

A collision occurs between a 2.43 kg particle traveling with velocity Upper V Overscript right-arrow EndScripts Subscript 1 Baseline equals left-parenthesis negative 4.49 m divided by s right-parenthesis i Overscript ? EndScripts plus left-parenthesis negative 4.18 m divided by s right-parenthesis j Overscript ? EndScripts and a 3.47 kg particle traveling with velocity Upper V Overscript right-arrow EndScripts Subscript 2 Baseline equals left-parenthesis 5.07 m divided by s right-parenthesis i Overscript ? EndScripts plus left-parenthesis negative 1.20 m divided by s right-parenthesis j Overscript ? EndScripts . The collision connects the two particles. What then is the (a)x component and (b)y component of their velocity? Express their velocity as a (c) magnitude and (d) angle from the +x axis?

Explanation / Answer

apply the law of Conservation as m1u1 + m2u2 = m1v1 + m2v2

so

here

m1u1 + m2u2 = (m1+m2) V

as they are connected toghter

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