SOLUTION Obtain the maximum voltage by comparison of the given expression for 2
ID: 1325194 • Letter: S
Question
SOLUTION Obtain the maximum voltage by comparison of the given expression for 2 the output with the general expression. Next, substitute to find the rms voltage of the source. Substitute this result into Ohm?s law to find the rms current. REMARKS Notice how the concept of rms values allows the handling of an AC circuit quantitatively in much the same way as a DC circuit. QUESTION The rms current in an AC circuit: (Select all that apply.) reverses direction many times per second. is an average current, and is therefore zero. measures the magnitude of the current, as a special kind of average. is the direct current that dissipates energy at the same rate as the AC current. PRACTICE IT Use the worked example above to help you solve this problem. An AC voltage source has an output of delta v = (1.96 X 10^2 V) sin 2 pi ft. This source is connected to a 1.16 X 10^2 ohm resistor as in the figure. Find the rms voltage and rms current in the resistor. V rms = V I rms A EXERCISE Use the values from PRACTICE IT to help you work this exercise. Find the maximum current in the circuit and the average power delivered to the circuit. I max = A P = WExplanation / Answer
V_rms = V_max / sqrt(2)
here V _max = 1.96 x 10^2 V
V_rms = 1.96 x 10^2 / sqrt2 = 1.39 x 10^2 Volt
I_rms = V_rms / R = 1.39 x 10^2 / 1.16 x10^2 = 1.19 A
..................................................
Imax = Vmax / R = 1.96 x 10^2 / 1.16 x10^2 = 1.69 A
Average Power = Vrms * Irms = 1.39 x 10^2 x 1.19 = 1.65 x 10^2 Watt
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