A proton moves to the right with a speed of v=100m/s, and enters the shaded regi
ID: 1324862 • Letter: A
Question
A proton moves to the right with a speed of v=100m/s, and enters the shaded region in the figure below, which has a uniform magnetic fiedld of magnitude B=0.5 T directed into the page. The region also contains two oppositely charged plates, which produce a uniform electric field in the region between them.
Find the DIRECTION and the MAGNITUDE of the electric field such that the proton will traverse the region of the magnetic and electric fields without being deflected. (You can neglect the influence of gravity).
A proton moves to the right with a speed of v=100m/s, and enters the shaded region in the figure below, which has a uniform magnetic fiedld of magnitude B=0.5 T directed into the page. The region also contains two oppositely charged plates, which produce a uniform electric field in the region between them. Find the DIRECTION and the MAGNITUDE of the electric field such that the proton will traverse the region of the magnetic and electric fields without being deflected. (You can neglect the influence of gravity).Explanation / Answer
Note that the force due to the B-field is
F(B) = q v B
which points upward, by right hand rule.
The force due to the E-field, meanwhile, is
F(E) = q E
(which must point downward to cancel the B force)
Thus, as the proton does not get deflected, these forces are equal (B force is upward, E force one is downward)
q v B = q E
Solving for E,
E = v B
As v = 100 m/s, B = 0.5 T,
E = 50 N/C, DOWNWARD [ANSWER]
DONE!
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.