A proton located at the origin is accelerated in the -y direction for a brief ti

Question

A proton located at the origin is accelerated in the -y direction for a brief time.

(a) How much time passes before a detector located at <0.25, 0, 0> m detects a radiative electric field?
s
(b) What is the direction of the radiative electric field observed at this location?
---Select--- +x -x +y -y +z -z 0 magnitude none of the above
(c) If the accelerated particle had been an electron instead of a proton, what would have been the direction of the radiative electric field at this location?
---Select--- +x -x +y -y +z -z 0 magnitude none of the above

Explanation / Answer

When a charged particle is accelerated electromagnetic radiation is emitted, whose speed is c

Part a)

distance from the origin to the point x = 0.25 m

c = d / t

t = d / c

t = 0.25 / 3108

t = 8.3 s 10-10 s

Part b)

an electromagnetic wave is a wave in which the directional perpendicular speed, the electric field and magnetic field are all mutually perpendicular

Consider this case

speed in the positive x-axis

whereby the E and B are the axes y, z

if acceleration where the charge is in the negative direction and

the electric force is F = q E force has the direction of E, so the induced field (Lenz's Law) is in the opposite direction +Y , this is what creates the electromagnetic wave

Answer. The electric field is in the direction of + Y

Part c)

in this case the force is F = - e E

so the force is opposite to the electric field and Lenz's law opposes this field. Consequently it goes in the direction of -Y

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