2 (1pt) A moving 3.3 kg block collides with a horizontal spring whose spring con

Question

2 (1pt) A moving 3.3 kg block collides with a horizontal spring whose spring constant is 322 N/m. The block compresses the spring a maximum distance of 12.5 cm from its rest position. The coefficient of kinetic friction between the block and the horizontal surface is 0.15 What is the work done by the spring in bringing the block so rest? REMEMBER. Work has a sign. How much mechanical energy is being dissipated by the force of friction while the block is being brought to rest by the spring? What is the speed of the Mock when it hits the spring?

Explanation / Answer

1/2mv^2=1/2kX^2+Friction force*distance

friction force=coefficient of friction *N(which is mg)

friction force=3.3*9.8*0.15=4.851

work done by friction=4.851*0.125=0.6063.........ans

work stored in spring as potential energy=1/2kX^2

= 5.03125/2=2.515........ans

conservation of energy=

1/2mv^2=1/2kX^2+Friction force*distance

1/2*3.3*V^2=2.515+0.6063

v=1.37m/sec..........ans

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