A conducting rod of mass 29 g and length 52 cm has holes drilled near each end s
ID: 1324511 • Letter: A
Question
A conducting rod of mass 29 g and length 52 cm has holes drilled near each end so that it is free to slide in a vertical direction along two conducting rails as shown in the figure below. A current of 190 A is made to flow through an identical rod at the bottom of the assembly and return through the sliding sliding rod. Determine the height of the sliding rod above the base rod when in equilibrium. Assume the horizontal rods are very long.
A conducting rod of mass 29 g and length 52 cm has holes drilled near each end so that it is free to slide in a vertical direction along two conducting rails as shown in the figure below. A current of 190 A is made to flow through an identical rod at the bottom of the assembly and return through the sliding sliding rod. Determine the height of the sliding rod above the base rod when in equilibrium. Assume the horizontal rods are very long.Explanation / Answer
apply force between parallel wires = gravitatioanl force
force between two parallel wires is given by F = u0i1i2L/2pid
where u0 = constnat = 4pi*10^-7 H/m,
i1, i2 are the currents ,
L s the length o the wire,
d is the distqance between these two wires
if current are in same directiion, there exists , they exert attractive force on each other
and
if currents are in opposite direction, they exert repulsive force
so here
mg = uoi1i2L/2pih
2pih = 4*3.14 e-7 * 190*190* 0.52/(0.029 * 9.8)
2pih = 0.0829
h = 0.0829/6.28)
h = 1.32 cm
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