11. (1pt) The escape velocity of a bullet from the surface of planet Y is 1983 m

Question

11. (1pt) The escape velocity of a bullet from the surface of planet Y is 1983 m/s. Calculate the escape velocity from the surface of the planet X if the mass of planet X is 1.45 times that of Y, and its radius is 0.791 times the radius of Y. Answer: Submit All Answers 12. [1pt] The small spherical planet called Glob has a mass of 7.10x10^18kg and a radius of 5.70x10^4m. An astronaut on the surface of Glob throws a rock straight up. The rock reaches a maximum height of 150x103m above the surface of the planet before it falls back down. What was the initial speed of the rock as it left the astronaut's hand? (Glob has no atmosphere, so no energy is lost to air friction.) 6.67E-11Nm^2/kg^2. Answer: Submit All Answers 13. [1 pt] A satellite is in a circular orbit very close to the surface of a spherical planet. The period of the orbit is T= 237 hours. What is density (mass/volume) of the planet? Assume that the planet has a uniform density. Answer: Submit All Answers

Explanation / Answer

1)The artificial gravity is provided by the centrifugal force (imagine yourself, shrunk, and inside the tubing of your bicycle tire. When that rotates, you get pressed to the outermost part of the inside and it will feel to you as if a gravitational force keeps you pressed to your "ground" )

Hence
v^2/R = g

V^2=R*g

=sqrt(26*9.8)

=15.9m/sec

b)F= GMm/r^2

G is Newtons constant, 6.673 x 10^-11
M is mass of Earth
m is mass of object
r is distance between them

F= 6.673 x 10^-11 x 5.98 x 10^24 x 3.000/6,370,000^2
F= 36.38 N

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